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5z^2-9z-6=0
a = 5; b = -9; c = -6;
Δ = b2-4ac
Δ = -92-4·5·(-6)
Δ = 201
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{201}}{2*5}=\frac{9-\sqrt{201}}{10} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{201}}{2*5}=\frac{9+\sqrt{201}}{10} $
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